x^2+12x=73

Solution for x^2+12x=73 equation:

x^2+12x=73

We move all terms to the left:

x^2+12x-(73)=0

a = 1; b = 12; c = -73;
Δ = b2-4ac
Δ = 122-4·1·(-73)
Δ = 436
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{436}=\sqrt{4*109}=\sqrt{4}*\sqrt{109}=2\sqrt{109}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-2\sqrt{109}}{2*1}=\frac{-12-2\sqrt{109}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+2\sqrt{109}}{2*1}=\frac{-12+2\sqrt{109}}{2}
$